A stone projected vertically up from the ground reaches a height y in its path at t1 seconds and after further t2 seconds reaches the ground. The height y is equal to
A
12g(t1+t2)
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B
12g(t1+t2)2
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C
12gt1t2
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D
gt1t2
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Solution
The correct option is C12gt1t2 y=ut1−12gt21 t1+t2⇓=2ug (total time of journey) So, u=g(t1+t2)2 ⇒y=g(t1+t2)2t1−12gt21=12gt1t2