wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

A stone projected with a velocity with a velocity u at an angle θ with the horizontal reaches maximum height H1. When it is projected with the velocity u at an angle (π2θ) with the horizontal, it reaches maximum height H2. The relation between the horizontal range R of the projectile, heights H1 and H2 is

A
R=4H1H2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
R=4(H1H2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
R=4(H1+H2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
R=H21H22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A R=4H1H2
H1=u2sin2θ2g
and H2=u2sin2(90θ)2g=u2cos2θ2g
H1H2=u2sin2θ2g×u2cos2θ2g=(u2sin2θ)216g2=R216
R=4H1H2.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Torque: How Much Does a Force Turn?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon