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1st Equation of Motion

a stone throw...

Question

a stone thrown upward attains the maximum height of 19.6m find he velocity with which it was thrown.

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Solution

Dear Student,

Given ,
H =19.6m ,
v =0, a = -g , u= ?
g=9.8m/s²
Now,

v²-u²=2as

=>-u²=-2gH

=>u²=2gh

=>u=√2gh

=>√29.819.6

=>√19.6*19.6

=>19.6m/s

Regards,

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