A stone thrown upwards with a speed of 20 metres per second loses speed at the rate of 9.8 metres every second. Find an algebraic expression which gives the speed of the stone at various times.

Open in App

Solution

Initial speed of the stone = 20 metres per second

Speed of the stone is decreased at the rate of 9.8 metres per second.

∴ After 1 second, speed of the stone = (20 − 1 × 9.8) metres per second

After 2 seconds, speed of the stone = (20 − 2 × 9.8) metres per second

After 3 seconds, speed of the stone = (20 − 3 × 9.8) metres per second

After t seconds, speed of the stone = (20 − t × 9.8) metres per second

= (20 − 9.8t) metres per second

∴ Algebraic expression for the speed of the stone at various times is 20 − 9.8t.

Suggest Corrections

Similar questions

100 m

25 m s^{- 1}

g = 10 m s^{- 2}

2

x

x

400 m

50 m/s

The line graph below shows people in a store at various times of the day.
What is the busiest time of the day at the store?

Join BYJU'S Learning Program