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Standard XII

Physics

Direction of Instantaneous Velocity

A stone throw...

Question

A stone thrown upwards with speed u attains maximum height h. Another stone thrown upwards from the same point with speed 2u attains maximum height H. What is the relation between h and H?

2h = H

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3h = H

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4h = H

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5h = H

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Solution

The correct option is C 4h = H
At max height, $v = 0 m / s$
$u^{2} = 2 g h$
$h = \frac{u^{2}}{2 g}$
$⟹ H = \frac{2 u^{2}}{2 g}$
$⟹ H = 4 (\frac{u^{2}}{2 g})$
$⟹ H = 4 h$

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A stone thrown upwards with speed u attains maximum height h. Another stone thrown upwards from the same point with speed 2u attains maximum height H. What is the relation between h and H?

The correct option is C 4h = HAt max height, v=0m/su2=2ghh=u22g⟹H=2u22g⟹H=4(u22g)⟹H=4h

The correct option is C 4h = H
At max height, $v = 0 m / s$
$u^{2} = 2 g h$
$h = \frac{u^{2}}{2 g}$
$⟹ H = \frac{2 u^{2}}{2 g}$
$⟹ H = 4 (\frac{u^{2}}{2 g})$
$⟹ H = 4 h$