A stone thrown vertically upwards with an initial velocity $u$ from the top of a tower, reaches the ground with a velocity of 3 $u$ . The height of the tower is :

3 u^{2} / g

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4 u^{2} / g

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6 u^{2} / g

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9 u^{2} / g

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Solution

The correct option is B $4 u^{2} / g$
If $h$ be the height of the tower, using formula $v^{2} = u^{2} + 2 a S$ ,
$(3 u)^{2} = u^{2} + 2 g h$
or $8 u^{2} = 2 g h$ or $h = 4 u^{2} / g$

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from the top of a tower of height h, a body is thrown vertically downwards with an initial velocity u. Simultaneously another body is thrown vertically upwards with an initial velocity u. In reaching the ground the additional time required by the body thrown upwards is?

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A stone thrown vertically upwards with an initial velocity u from the top of a tower, reaches the ground with a velocity of 3u. The height of the tower is :

The correct option is B 4u2/gIf h be the height of the tower, using formula v2=u2+2aS, (3u)2=u2+2ghor 8u2=2gh or h=4u2/g

A stone thrown vertically upwards with an initial velocity $u$ from the top of a tower, reaches the ground with a velocity of 3 $u$ . The height of the tower is :

The correct option is B $4 u^{2} / g$
If $h$ be the height of the tower, using formula $v^{2} = u^{2} + 2 a S$ ,
$(3 u)^{2} = u^{2} + 2 g h$
or $8 u^{2} = 2 g h$ or $h = 4 u^{2} / g$