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Question

A stone tied to one end of string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 10 revolutions in 20 s, the magnitude of the acceleration of the stone is close to

A
98.6 cms2
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B
490 cms2
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C
987 cms2
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D
996 cms2
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Solution

The correct option is C 987 cms2
Radius of circle, r=1 m=100 cm
Stone makes 10 revolutions per 20 sec
revolutions per second (f) is 0.5
Now angular velocity (ω)=2πf=π rad/s
centripetal accelaretion=ω2r=π2×100 cm/s2
centripetal acceleration = 987 cm/s2

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