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Byju's Answer

Standard XII

Physics

Law of Conservation of Mechanical Energy

A stone tied ...

Question

A stone tied to the end of a 20 cm long string is whirled in a horizontal circle. If the centripetal acceleration is 9.8 ${m s}^{- 2},$ its angular speed in radian/sec is:

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Solution

The correct option is A 7
Given that Radius of horizontal circle R = 0.20 m.
Centripetal acceleration = $a_{c} = 9.8 m / s^{2}$ .
Angular speed $= ω = ?$

As we know that centripetal acceleration = $a_{c} = r ω^{2}$
9.8 = 0.20 * ω²
ω = 7 rad/sec.

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A stone tied to the end of a 20 cm long string is whirled in a horizontal circle. If the centripetal acceleration is 9.8 ms−2, its angular speed in radian/sec is:

The correct option is A 7Given that Radius of horizontal circle R = 0.20 m. Centripetal acceleration = ac=9.8m/s2. Angular speed =ω=?As we know that centripetal acceleration = ac=rω2 9.8 = 0.20 * ω² ω = 7 rad/sec.

A stone tied to the end of a 20 cm long string is whirled in a horizontal circle. If the centripetal acceleration is 9.8 ${m s}^{- 2},$ its angular speed in radian/sec is:

The correct option is A 7
Given that Radius of horizontal circle R = 0.20 m.
Centripetal acceleration = $a_{c} = 9.8 m / s^{2}$ .
Angular speed $= ω = ?$

As we know that centripetal acceleration = $a_{c} = r ω^{2}$
9.8 = 0.20 * ω²
ω = 7 rad/sec.