Question

A stone tied to the end of a string 100 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 22 s, then the acceleration of the stone is then

• A. 16 $m{s}^{-2}$
• B. 4$m{s}^{-2}$
• C. 12$m{s}^{-2}$
• D. 8$m{s}^{-2}$

Answer 1

The correct option is A 16 $m{s}^{-2}$

Here, $r=100cm=1m$
Frequency, $\nu$ = $\frac{14}{22}rps$
$\therefore$ $\omega =2\pi \nu =2\times \frac{22}{7}\times \frac{14}{22}$ = $4rad{s}^{-1}$
The acceleration of the stone is
$a_c={\omega }^{2}r=\left(4{)}^2\right(1)=16m{s}^{-2}$