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Question

A stone weighing 1 kg is whirled in a vertical circle at the end of a rope of length 0.5 m. Stone completes the vertical circle with minimum possible speed. The velocity of the stone midway, when the string is horizontal is (Take g=10 m/s2)

A
20 m/s
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B
5 m/s
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C
15 m/s
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D
3 m/s
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Solution

The correct option is C 15 m/s

Since, the stone is just completing the vertical circle.
VA=gR
Applying law of conservation of energy at A and B
UA+KEA=UB+KEB
mg(2R)+12m(gR)2=mg(R)+12mv2B
mgR+12m(gR)=12mv2B
vB=3gR
vB=15 m/s
(R=0.5 m)

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