A stone weighing 200 g is dropped in the given beaker, the water level in it rises to 400 ml. What would have been the rise in water level if a stone weighing 300 g would have been dropped in the beaker?
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Solution
Initial water level in the beaker = 200 ml.
Water level in the beaker after dropping a 200 g of stone in it = 400 ml.
So, the rise in water level = 400 ml - 200 ml = 200 ml.
Rise in water level for 200 g stone = 200 ml.
Rise in water level for each g of stone = 1 ml.
ise in water level for 300 g stone = 1 x 300 = 300 ml.
So, the water level would have risen by 300 ml.