A stone weight 392.4 N in air and 196.2 N IN water. Compute the volume of stone and its specific gravity.

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Solution

Let the volume of stone is $V$ t is density.
$\begin{matrix} V d g = 392.4...... (1) V δ g = 392.4 - 196.2 V (1000) g = 196.2....... (2) v = \frac{196.2}{10^{4}} m^{3} = 1.962 \times 10^{- 2} m^{3} \end{matrix}$
Also, from (i) & (ii)
$d = 2000$
$∴$ specific gravity $= 2$
& volume $= 1.96 \times 10^{- 2} m^{3}$

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A stone weight 392.4 N in air and 196.2 N IN water. Compute the volume of stone and its specific gravity.

Let the volume of stone is V t is density.Vdg=392.4......(1)Vδg=392.4−196.2V(1000)g=196.2.......(2)v=196.2104m3=1.962×10−2m3Also, from (i) & (ii)d=2000∴specific gravity =2& volume =1.96×10−2m3