Question

A stone weight 392.4 N in air and 196.2 N IN water. Compute the volume of stone and its specific gravity.

Answer 1

Let the volume of stone is $V$ t is density.

$\begin{array}{c}Vdg=\mathrm{392.4......}\left(1\right)\\ V\delta g=392.4-196.2\\ V\left(1000\right)g=\mathrm{196.2.......}\left(2\right)\\ v=\frac{196.2}{{10}^4}{m}^3\\ =1.962\times {10}^{-2}{m}^3\end{array}$

Also, from (i) & (ii)

$d=2000$

$\therefore$specific gravity $=2$

& volume $=1.96\times {10}^{-2}{m}^3$