Question

A stone with weight W is thrown vertically upward into the air from ground level with intial speed $v_6$. if a constant force F due to air drag acts on the stone throughout its flight. the maximum height intiatined by the stone is

• A. $h=\frac{v^2}{2g\left(1+\frac{f}{w}\right)}$
• B. $h=\frac{v_0^2}{2g\left(1-\frac{r}{w}\right)}$
• C. $h=\frac{v_0^2}{g\left(1-\frac{w}{f}\right)}$
• D. $h=\frac{v_0^2}{2g\left(1-\frac{w}{f}\right)}$

Answer 1

The correct option is B $h=\frac{v_0^2}{2g\left(1-\frac{r}{w}\right)}$

$W+F=ma----\left(i\right)m=\frac{W}{g}----\left(ii\right)W+F=\frac{W}{g}a⟹a=\frac{W+F}{W}g\therefore H_{max}=\frac{v^2}{2a}=\frac{v^2}{2g(1+\frac{F}{W})}$