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Question

A storage battery of emf 8.0 V and internal resistance 0.5Ω is being charged by a 120 V dc supply using a series resistor of 15.5Ω. What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit?

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Solution

E=8V, internal resistance R1=0.5Ω
V=120V, resistance R2=15.5Ω
Effective voltage V=VE=112 V
I=VR1+R2=7 A
Voltage across R1=IR1=3.5 V
Terminal voltage =8+3.5=11.5 V
Series resistor in the charging circuit limits the current drawn from the external source.

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