A storage battery of emf 8-0 V and internal resistance 0-5 - is being charged by a 120 V dc supply using a series resistor of 15-5 - What is the terminal voltage of the battery during charging- What is the purpose of having a series resistor in the charging circuit-

Apply KVL in ABCD 8 0. 5 _ i 15. 5 _ i +120=0 112= 16 _ i i= 112 16 A i=7ABy Going from point B to C: V _ B 8 0.5× 7 V_C=0V _ B V _C=(8+3.5)VTerminal ...

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Byju's Answer

Standard XII

Physics

Kirchoff's Voltage Law

A storage bat...

Question

A storage battery of emf $8.0 V$ and internal resistance $0.5 Ω$ is being charged by a $120 V$ dc supply using a series resistor of $15.5 Ω$ . What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit?

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Solution

Apply KVL in ABCD
$- 8 - 0. 5_{i} - 15. 5_{i} + 120 = 0 112 = 16_{i} i = \frac{112}{16} A i = 7 A$
By Going from point B to C:-
$V_{B} - 8 - 0.5 \times 7 - V_{C} = 0$
$V_{B} - V_{C} = (8 + 3.5) V$
Terminal voltage = 11.5V
$\to$ A series resistance in the charging circuit reduces the current value in the circuit. If resistor will not be there current will be extremely high.

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A storage battery of emf 8.0 V and internal resistance 0.5Ω is being charged by a 120 V dc supply using a series resistor of 15.5Ω. What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit?

A storage battery of emf $8.0 V$ and internal resistance $0.5 Ω$ is being charged by a $120 V$ dc supply using a series resistor of $15.5 Ω$ . What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit?