A store room in the form of a cuboid has measures $42 m \times 35 m \times 21 m$ . How many cuboidal boxes can be stored in it if the volume of one box is $0.7 m^{3}$ ?

$30870$

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$44000$

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$44100$

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$42000$

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Solution

The correct option is C
$44100$

Given: Volume of one box $= 0.7 m^{3}$

Volume of the store room $= 42 \times 35 \times 21$
$= 30870 m^{3}$

Number of boxes that can be stored in the room
$= \frac{Volume of the room}{Volume of one box} = \frac{30870}{0.7}$
$= 44100$
So, The number of cuboidal boxes that can be stored in the room is $44100$

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A store room in the form of a cuboid has measures 42m×35m×21m. How many cuboidal boxes can be stored in it if the volume of one box is 0.7m3?

The correct option is C 44100 Given: Volume of one box =0.7 m3 Volume of the store room =42×35×21 =30870 m3 Number of boxes that can be stored in the room =Volume of the roomVolume of one box=308700.7 =44100 So, The number of cuboidal boxes that can be stored in the room is 44100

A store room in the form of a cuboid has measures $42 m \times 35 m \times 21 m$ . How many cuboidal boxes can be stored in it if the volume of one box is $0.7 m^{3}$ ?