A straight chain hydrocarbon has the molecular formula $C_{7} H_{10}$ . The hybridization of the carbon atoms form one end of the chain to the other are respectively.
$s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be:

C H_{3} - C \equiv C C H_{2} - C H = C H C H = C H_{2}

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C H_{3} C H_{2} - C H = C H C H_{2} - C \equiv C H

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C H_{3} C H = C H C H_{2} - C \equiv C C H = C H_{2}

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C H_{3} C H = C H C H_{2} - C H = C H C \equiv C H

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Solution

The correct option is D $C H_{3} C H = C H C H_{2} - C H = C H C \equiv C H$
$C H_{3} s p^{3} C H s p^{2} = C H s p^{2} C H_{2} s p^{3} - C H s p^{2} = C H s p^{2} C s p \equiv C H s p$

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A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

The hybridizations of the carbons numbered 1, 3 and 5 in the given hydrocarbon are respectively:

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

The hybridizations of the carbons numbered 1, 3 and 5 in the given hydrocarbon sequentially are:

Q. In the hydrocarbon

C (1) H_{2} = C (2) H - C (3) \equiv C H

, the state of hybridisation of carbons 1, 2 and 3 respectively are:

Q. In the hydrocarbon

C (1) H_{2} = C (2) H - C (3) \equiv C H

, the state of hybridisation of carbons 1, 2 and 3 respectively are:

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A straight chain hydrocarbon has the molecular formula C7H10. The hybridization of the carbon atoms form one end of the chain to the other are respectively. sp3,sp2,sp2,sp3,sp2,sp and sp. The structural formula of the hydrocarbon would be:

The correct option is D CH3CH=CHCH2−CH=CHC≡CHCH3sp3CHsp2=CHsp2CH2sp3−CHsp2=CHsp2Csp≡CHsp

A straight chain hydrocarbon has the molecular formula $C_{7} H_{10}$ . The hybridization of the carbon atoms form one end of the chain to the other are respectively.
$s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be:

The correct option is D $C H_{3} C H = C H C H_{2} - C H = C H C \equiv C H$
$C H_{3} s p^{3} C H s p^{2} = C H s p^{2} C H_{2} s p^{3} - C H s p^{2} = C H s p^{2} C s p \equiv C H s p$