wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A straight conducting rod of length 2 m is moved with a speed of 2 m/s in a uniform magnetic field of magnitude 10 T. The maximum induced emf across the ends of the rod can be

[0.77 Mark]

A
10 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
40 V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
56 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 40 V
As we know that, emf,

E=ba(v×B)dl

Emax=Bvl=10×2×2=40 V

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon