wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A straight conducting rod PQ is executing SHM in xyplane from x=d to x=+d. Its mean position is x=0 and its length is along y axis. There exists a uniform magnetic field B from x=d to x=0 pointing inward normal to the paper and from x=0 to =+d there exists another uniform magnetic field of same magnitude B but pointing outward normal to the plane of the paper. At the instant t=0, the rod is at x=0 and moving to the right. The induced emf (ε) across the rod PQ vs time (t) graph will be

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B
At mean position, velocity is maximum. Hence motional emf |Bvl| is also maximum. v oscilIates simple harmonically. Hence, motional emf will also be sinusoidal. Further, polarity of induced emf will keep on changing.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Expression for SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon