A straight conductor 0.1 m long moves in a uniform magnetic field ).1T. The velocity of the conductor is 15 m/s and is directed perpendicular to the field. The e.m.f. induced between the two ends of the conductors is.
A
0.10 V
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B
0.15 V
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C
1.50 V
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D
15.00 V
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Solution
The correct option is A 0.15 V ε=BvI=0.1×15×0.1=.15V(considering B, and v are mutually perpendicular)