A straight conductor carrying a current $i$ is split into identical semicircular turns of radius $r$ as shown in the figure. The magnetic induction at the center C of the circular loop is:

\frac{μ_{0} i}{4 r}

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\frac{μ_{0} i}{8 r}

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\frac{μ_{0} i}{2 r}

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zero

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Solution

The correct option is B zero
Due to anti-clockwise current, the magnetic field will be out of the plane.
& Due to clockwise current, the magnetic field will be into the plane.
they will cancel out each other
Net $| B | = 0$

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A straight conductor carrying a current i is split into identical semicircular turns of radius r as shown in the figure. The magnetic induction at the center C of the circular loop is:

The correct option is B zeroDue to anti-clockwise current, the magnetic field will be out of the plane.& Due to clockwise current, the magnetic field will be into the plane.they will cancel out each otherNet |B|=0

A straight conductor carrying a current $i$ is split into identical semicircular turns of radius $r$ as shown in the figure. The magnetic induction at the center C of the circular loop is:

The correct option is B zero
Due to anti-clockwise current, the magnetic field will be out of the plane.
& Due to clockwise current, the magnetic field will be into the plane.
they will cancel out each other
Net $| B | = 0$