A straight horizontal conducting rod of length 0.5 m and mass 50 g is suspended by two vertical wires at its ends. A current of 5.0 A is set up in the rod through the wires. What magnetic field should be set up normal to the conductor in order that the tension in the wires is zero? Ignore the mass of the wires and take g = 10 $m s^{- 2}$ .

0.1 T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.2 T

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.3 T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.4 T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
0.2 T

In order that the tension in the supporting wires is zero the downward gravitational force mg on the rod must be balanced by an upward force BIl due to magnetic field, i.e. BIl = mg
$o r B = \frac{m g}{I l} = \frac{50 \times 10^{- 3} \times 10}{5 \times 0.5} = 0.2 T$
Hence the correct choice is (b).

Suggest Corrections

Similar questions

Q. A straight horizontal conducting rod of length

0.5 m

and mass

50 g

is suspended by two vertical wires at its ends. A current of

5.0 A

is set up in the rod through the wires. Then the magnetic field set up normal to the conductor in order that the tension in the wires is zero is (ignore the mass of the wire and take

g = 10 m s^{- 2}

) :

A straight horizontal conducting rod of length 0.5 m and mass 50 g is suspended by two vertical wires at its ends. A current of 5.0 A is set up in the rod through the wires. What magnetic field should be set up normal to the conductor in order that the tension in the wires is zero? Ignore the mass of the wires and take g = 10 $m s^{- 2}$ .

A straight horizontal conducting rod of length 0.45 m and mass 60 g is suspended by two vertical wires at its ends. A current of 5.0 A is set up in the rod through the wires.

(a) What magnetic field should be set up normal to the conductor in order that the tension in the wires is zero?

(b) What will be the total tension in the wires if the direction of current is reversed keeping the magnetic field same as before? (Ignore the mass of the wires.) g = 9.8 m s⁻².

Q. A straight horizontal conducting rod of 30 cm and mass 90 grams is suspended by two vertical wires at its ends. A current of 8A is setup in rod through wires. What should be the magnetic field (setup normal to conductor) so that tension in wires become zero.

Join BYJU'S Learning Program

The correct option is B 0.2 T In order that the tension in the supporting wires is zero the downward gravitational force mg on the rod must be balanced by an upward force BIl due to magnetic field, i.e. BIl = mg or B=m gIl=50×10−3×105×0.5=0.2 T Hence the correct choice is (b).