CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A straight line AB is 8 cm long. Locate by construction the locus of a point which is:

(i) Equidistant from A and B.

(ii) Always 4 cm from the line AB.

(iii) Mark two points X and Y, which are 4 cm from AB and equidistant from A and B, Name the figure AXBY.


Open in App
Solution

Step of Construction:

(i) Draw AB is 8 cm, Draw PQ the perpendicular bisector of AB.

(ii) Draw CD and EF both parallel to AB and each at a distance of 4 cm from AB.

(iii) AXBY is a square.


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Locus of the Points Equidistant from a given point
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon