Question

A straight line conductor of length 0.4 m is moved with a speed of 7 m/s perpendiculars to a magnetic field of intensity 0.9 Wb/m².

The induced e.m.f. across the conductor is

(a) 5.04 V

(b) 25.2 V

(c) 1.26 V

(d) 2.52 V

• A. $5.04V$
• B. $25.2V$
• C. $1.26V$
• D. $2.52V$

Answer 1

The correct option is D

$2.52V$

A 0.4 m long straight line conductor moves at 7 m/s perpendicular to a magnetic field with an intensity of 0.9 Wb/m2.

The induced e.m.f. across the conductor must be determined.

Conductor's length, $l=0.4m$

Speed, $v=7m/s$

Field of magnetic attraction ,$B=0.9Wb/m^2.$

Induced e.m.f.

$\begin{array}{rcl}\left(\epsilon \right)& =& Blv\\ & =& 0.9x0.4x7\\ & =& 2.52V\end{array}$

Therefore the induced e.m.f. across the conductor is $2.52V.$