A straight line is drawn curring two equal circles and passing through M the midpoint of the line joining the centres O and O'. Chord AB is equal to chord CD
True
Draw OP ⊥ AB and O'Q ⊥ CD
In △ MOP and △ MO'Q
∠ OMP = ∠ O'MQ (vertically opposite angles)
∠ OPM = ∠ O'QM = 90o
OM = O'M (given)
Hence the two triangles are congruent by AAS criteria
⇒ OP = O'Q (cpct)
Chords that are equidistant from the centre are equal in length - Hence AB = CD