A straight line is drawn parallel to the conjugate axis of the hyperbola x2a2−y2b2=1 to meet it and the conjugate hyperbola respectively in the point P and Q. The normals at p and Q to the curves meet on
A
x−axis
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B
y−axis
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C
y=x
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D
y=−x
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Solution
The correct option is Ax−axis
Equation of hyperbola →x292−y262=1
Conjugate hyperbola →y262−x292=1
Line || to conjugate axis of hyperbola (y−axis) is drawn to meet conjugate axis at P & Q which are symmetric points about x−axis then