A straight line is parallel to the line y=2x passes through Q(2,3) and cuts the line2x+4y−21=0 at P then find the coordinates of P
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Solution
Equation of line 11 to the line y−2x=0 will be y−2x≠k . It passes through (2,3)∴3−2(2)=k⇒k=−1 Hence, eqn of line=y−2x+1=0 it cuts the line 2x+4y−21=0 at P point ∴ solving both the equations we get y=4 and x=2.5P(2.5,4)