A straight line passes through the points of intersection x−2y−2=9 and 2x−bx−6=0 and the origin. Then the complete set of values ob b for which the acute angle between this line and y=0 is less 45o is
A
(−∞,4)∪(7,∞)
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B
(−∞,5)∪(7,∞)
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C
(−∞,4)∪(5,7)∪(7,∞)
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D
(−∞,4)∪(4,5)∪(7,∞)
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Solution
The correct option is B(−∞,5)∪(7,∞) Solvingthegivenequationx−2y−2=02y−6y−6=0−−−−−−−−−−−y(6−4)=2∴y=24−6Puttingxwegetx=12−264−6equnoflinepassingthrough(0,0)and(12−264−6,267−6)y−0=212−16(x−0)y=16−6.xm=tanθθ<45∘m<1&m<1∣∣∣16−b∣∣∣<1b<5−−−−(1)andb>7Oncombaingweget(−∞,5)∪(7,∞)Hence,optionBisthecorrectanswer.