A straight line passing through the point $A (3, 4)$ is such that its intercept between the axes is bisected at A. Then its equation is-

3 x - 4 y + 7 = 0

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4 x + 3 y = 24

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3 x + 4 y = 25

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x + y = 7

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Solution

The correct option is B $4 x + 3 y = 24$
A is the midpoint of the line joining the points (0,b) and ( a,0)
$\frac{a + 0}{2} = 3$ $\Rightarrow a = 6$
$\frac{0 + b}{2} = 4$ $\Rightarrow b = 8$

$\frac{x}{a} + \frac{y}{b} = 1$
Putting the values of a and b in the equation $4 x + 3 y - 24 = 0$

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Similar questions

P (- 3, 4)

P

A (3, 4)

A

Find the equation of a straight line which passes through the point (3, 4) and sum of its intercepts on the x and y axis is 14.

x - y = 1

2 x - 3 y + 1 = 0

3 x + 4 y = 14

5 x - y + 4 = 0

3 x + 4 y - 4 = 0

(1, 5)

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