Question

A straight line through the point A(3,4) is such that its intercept between the axes is bisected at A.Its equation is

Answer 1

Let P(0,b) and Q(a,0). A is the mid-point of PQ.

$\frac{a+0}{2}=3$

$a=6$

$\frac{b+0}{2}=4$

$b=8$

Therefore,

Equation of line is $\frac{x}{6}+\frac{y}{8}=1$

$4x+3y=24$