Question

A straight line was obtained on plotting $\frac{dx}{dt}vs{\log }_{10}(a-x)$ with an intercept on $\left(\frac{dx}{dt}\right)$ axis equal to $0.6021$. The rate constant for the reaction is _______ litre${}^{n-1}$ mol${}^{1-n}$ t${}^{-1}$.

Answer 1

The intercept will be $\frac{K}{2.303}$,

So $\frac{K}{2.303}=.6021$

$K=2.303\times .6021=1.38L^{n-1}mo{l}^{1-n}{t}^{-1}$