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Production

Oblique Cutting - II

A straight tu...

Question

A straight turning operation is carried out using a single point cutting tool on an $A I S I 1020$ steel rod. The feed is $0.2 m m / r e v$ and the depth of cut is $0.5 m m$ . The tool has a side cutting edge angle of $60^{o}$ . The uncut thickness (in $m m$ ) is
0.1

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Solution

The correct option is A 0.1

$θ + Ψ = 90^{o}$
$θ = 90^{o} - 60^{o} = 30^{o}$
$f^{'}$ (uncut chip thickness)
= $f s i n θ = 0.2 \times s i n 30^{o} = 0.1 m m$

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A straight turning operation is carried out using a single point cutting tool on an AISI1020 steel rod. The feed is0.2mm/rev and the depth of cut is 0.5mm. The tool has a side cutting edge angle of 60o. The uncut thickness (in mm) is0.1

The correct option is A 0.1 θ+Ψ=90o θ=90o−60o=30o f′ (uncut chip thickness) =fsinθ=0.2×sin30o=0.1mm

A straight turning operation is carried out using a single point cutting tool on an $A I S I 1020$ steel rod. The feed is $0.2 m m / r e v$ and the depth of cut is $0.5 m m$ . The tool has a side cutting edge angle of $60^{o}$ . The uncut thickness (in $m m$ ) is
0.1

The correct option is A 0.1

$θ + Ψ = 90^{o}$
$θ = 90^{o} - 60^{o} = 30^{o}$
$f^{'}$ (uncut chip thickness)
= $f s i n θ = 0.2 \times s i n 30^{o} = 0.1 m m$