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Question

# A straight wire of length 0.5 m and carrying a current of 1.2 ampere is placed in uniform magnetic field of induction 2 Tesla. The magnetic field is perpendicular to the length of the wire. The force on the wire is

A
1.2 N
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B
2.4 N
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C
3.0 N
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D
2.0 N
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Solution

## The correct option is A 1.2 NGiven: l=0.5 m i=1.2 A B=2 T The magnetic force on wire is given by F=i(l×B) F=ilBsinθ Where θ= Angle between l and B According to question , θ=90∘ As sin90∘=1 ∴F=1.2×0.5×2 F=1.2 N Hence, option (B) is correct option.

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