wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A straight wire of length (π2) metre is carrying a current of 2A and the magnetic field due to it is measured at a point distant 1 cm from it. If the wire is to be bent into a circle and is to carry the same current as before, the ratio of the magnetic field at its centre to that obtained in the first case would be

A
50 : 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1 : 50
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
100 : 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1 : 100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1 : 50
If a wire of length l is bant in the form of a circle of radius r then
2πr=l r=l2π
F=i(L×B)
Magnetic field due to straight wire B1=μ04π.2ir=μ04π×2×21×102 also magnetic
field due to circular loop B2=μ04π.2πir=μ04π.2π×2π/2 B2B1=150

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Magnetic Field Due to a Current Carrying Wire
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon