A straw $6 c m$ long floats on water. The water film on one side has surface tension of $50 d y n / c m$ . On the other slide, camphor reduces the surface tension to $40 d y n / c m$ . The resultant force acting on the straw is

(50 \times 6 - 40 \times 6) d y n

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10 d y n

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(\frac{50}{6} - \frac{40}{6}) d y n

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90 d y n

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Solution

The correct option is A $(50 \times 6 - 40 \times 6) d y n$

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A straw 6 cm long floats on water. The water film on one side has surface tension of 50 dyn/cm. On the other slide, camphor reduces the surface tension to 40 dyn/cm. The resultant force acting on the straw is

The correct option is A (50×6−40×6)dyn

A straw $6 c m$ long floats on water. The water film on one side has surface tension of $50 d y n / c m$ . On the other slide, camphor reduces the surface tension to $40 d y n / c m$ . The resultant force acting on the straw is

The correct option is A $(50 \times 6 - 40 \times 6) d y n$