Question

A stretched string is $1.5m$ & has a linear density of $1.6g/cm$. What tension in string will result in second overtone of $150Hz$? (String is clamped at both end)

• A. $32.4\times {10}^{2}N$
• B. $32.4\times {10}^{3}N$
• C. $324N$
• D. $32.4N$

Answer 1

The correct option is B $32.4\times {10}^{3}N$


$n_2=3n=3\times 150=450=\frac{v}{\lambda }450=\frac{v}{\lambda }\Rightarrow \frac{\lambda }{2}=0.5\lambda =1450=\frac{v}{1}v=450m/sT=m{v}^2=\frac{1.6\times {10}^{-3}}{{10}^{-2}}\times 450\times 450T=32400N=32.4\times {10}^{3}N$