A stretched string is vibrating according to the equation y=5sin(πx2)cos4πt, where y and x are in cm and t is in sec. The distance between two consecutive nodes on the string is
A
2cm
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B
4cm
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C
8cm
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D
16cm
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Solution
The correct option is A2cm Given, equation of standing wave is y=5sin(πx2)cos4πt Compare the given equation with standard equation of standing wave. y=2Asinkxcosωt k=2πλ=π2 ⇒λ=4 cm Hence, distance between two consecutive nodes is λ2=2 cm