A stretched wire of some length under a tension is vibrating with its fundamental frequency. Its length is decreased by 45% and tension is increased by 21%. Now its fundamental frequency:
A
increases by 50%
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B
increases by 100%
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C
decreases by 50%
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D
decreases by 25%
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Solution
The correct option is B increases by 100% length is decreased by 45%⇒l′=55l100 Tension is increased by 21%⇒T′=121T100 f=l2l√Tμ f1f2=55100×10011 f1f2=12 f2=2f1 f is increased 100%