A stretching force of 10N is applied at one end of a spring balance and an equal force is applied at the other end in the opposite direction at the same time. The reading of the balance is:
A
5N
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B
10N
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C
20N
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D
0
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Solution
The correct option is B10N Actual Scenario : Tension in the spring =10N Opposite force in the spring =10N Modified Scenario : The opposite force is replaced by the force that is acting in the same direction.Here equal and opposite forces are applied on the spring, hence it will remain in the stretched position and the total force acting on it is 10N Reading in the spring balance =10N