A string 1 m long is drawn by a 300 Hz vibrator attached to its end. The string vibrates in three segments. The speed of transverse waves in the string is equal to

100 m/s

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200 m/s

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300 m/s

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400 m/s

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Solution

The correct option is A 200 m/s
The string vibrates in 3 segments, this implies there are 2 crests, one trough (or vice versa).
Hence $\frac{3}{2} λ = 1$
$λ = \frac{2}{3} m$
Now we know $f = 300 H z$
$v = f λ = 300 \times \frac{2}{3} = 200 m s^{- 1}$
Hence option B.

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A string 1 m long is drawn by a 300 Hz vibrator attached to its end. The string vibrates in three segments. The speed of transverse waves in the string is equal to

The correct option is A 200 m/sThe string vibrates in 3 segments, this implies there are 2 crests, one trough (or vice versa).Hence 32λ=1λ=23mNow we know f=300Hzv=fλ=300×23=200ms−1Hence option B.

The correct option is A 200 m/s
The string vibrates in 3 segments, this implies there are 2 crests, one trough (or vice versa).
Hence $\frac{3}{2} λ = 1$
$λ = \frac{2}{3} m$
Now we know $f = 300 H z$
$v = f λ = 300 \times \frac{2}{3} = 200 m s^{- 1}$
Hence option B.