A string 120cm in length sustains a standing wave, with the points of string at which the displacement amplitude is equal to √2mm being separated by 15.0cm. The maximum displacement amplitude is
A
2mm
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B
10mm
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C
15mm
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D
25mm
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Solution
The correct option is A2mm ηλ2=120⇒1s=η(λ4) at x=λ4;amplitudeA1=√2A =√2(√2) =2mm