Question

a string breaks under a load of 4.8 kg. A mass if 0.5 kg is attached to one end of the string 2m long and is rotated in a horizontal circle. calculate the greatest no of revolutions that the mass can make without breaking the string

• A. >7
• B. <7
• C. 7
• D. 0

Answer 1

The correct option is A >7

Mass of load$=4kg$

Mass attached$=0.5kg$

String's length$=2m$

$T_{max}=4.5kg\Rightarrow 48N$

See image

$m{\omega }^{2}R>T_{max}m{\omega }^{2}R=48N0.5\times {\omega }^2\times 2>48N{\omega }^2>48\omega >7\left(approx\right)$