wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A string can bear a maximum tension of 3.16kgwt. What maximum number of revolutions per second can be made by a stone of mass 49g tied to one end of a 1m long piece of this string so that the string may not break? (π=22/7)

Open in App
Solution

length of string,r=1m
the maximum tension in the string T=3.16kgwt
=3.16×10
T=31.6N
mass of stone m=49g=0.049kg
the maximum tension in the string,T=mv2r+mg
31.6=0.049×v212+0.049×1031.6=0.049v2+0.49v2=31.60.490.049v2=31.110.049v=634.89v=25.19m/s
v=rww=vr=25.191=25.19w=2πnn=w2π=25.192×3.14=25.196.25=4.01n=4.01


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circular Motion: A Need for Speed
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon