Question

A string fixed at both ends oscillates in $5$ segments, length $10m$ and the velocity of the wave is $20m{s}^{-1}$. What is the frequency?

• A. $5Hz$
• B. $15Hz$
• C. $10Hz$
• D. $2Hz$

Answer 1

The correct option is A

$5Hz$

Step1: Given data.

Number of segment, $n=5$

Length of the string, $L=10m$

Velocity of the wave, V=$20\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right.$

Step2: Finding the frequency.

We know that,

Frequency of the standing wave, $f=\frac{nV}{2L}$

$f=\frac{5\times 20}{2\times 10}$

$f=5Hz$

Hence, option A is correct.