A string is stretched between fixed points separated by 75.0cm. It is observed to have resonant frequencies of 420Hz and 315Hz. There are no other resonant frequencies between these two. The lowest resonant frequency for this string is
A
105Hz
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B
305Hz
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C
205Hz
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D
10.5Hz
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Solution
The correct option is A105Hz Frequency : f=v2Ln, where v is the velocity of sound, n is an integer and f is the frequency. The highest common factor will be the fundamental frequency. HCF of 420 and 315 is 105. Hence, the resonant frequency is 105Hz.