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Question

A string is wrapped around the rim of a wheel of moment of inertia 0.20 kgm2 and radius 20 cm. The wheel is free to rotate about its axis initially the wheel is rest. The string is now pulled by a force of 20N. The angular velocity of the string after 5 seconds will be :
1030436_06ce4fdf21a045ba8c56b887ad3ff519.png

A
90 rad/s
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B
70 rad/s
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C
95 rad/s
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D
100 rad/s
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Solution

The correct option is D 100 rad/s
torque=T×r=Iα
20×0.2=0.2α
α=20
ω=αt=20×5=100rad/sec

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