A string is wrapped on a wheel of moment of inertia 0.2kg m2 and radius 10cm and passes over a light pulley to support a block of mass 2kg as shown in figure. Find the acceleration of the block.
A
0.89ms−2
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B
1.12ms−2
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C
0.69ms−2
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D
None
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Solution
The correct option is A0.89ms−2 Applying Newton's second law for the block, mg−T=ma ⇒2a=2g−T....(1)
And applying the rotational form of Newton's law for the pulley, T.r=Iα
or T=Ir2a=0.2a(0.1)2=20a....(2)
From equations (1) and (2), a=2g(2+20)=0.89ms−2