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Question

A string is wrapped over the edge of a uniform disc and the free end is fixed with the ceiling. The disc moves down. unwinding the string. Find the downward acceleration of the disc.

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Solution

Let the radius of the disc =R
Therefore according to the question & figure
MgT=ma

The torque about the center
=T×R=1×α

TR=(1/2)mR2×a/R

T=(1/2)ma
Putting this value in the equation (1)
we get
mg(1/2)ma=ma
mg=3/2 maa=2g/3

1568185_1213025_ans_4dbbf48a9d1947ecbfff6af41ae0675c.png

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