A string of length $1.5 m$ is tied to a stone of mass of $0.2 k g$ and is made to revolve at a speed of $1.2 m s^{- 1}$ . What is the centripetal force experienced by the stone?

0.173 N

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0.192 N

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0.160 N

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0.123 N

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Solution

The correct option is B $0.192 N$
Given:
Mass of the stone, $m = 0.2 k g$
Length of the string, $r = 1.5 m$
Speed of revolution, $v = 1.2 m s^{- 1}$
Centripetal force, $F = \frac{m v^{2}}{r} = \frac{0.2 \times (1.2)^{2}}{1.5} = \frac{0.288}{1.5}$
$⟹ F = 0.192 N$

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A string of length 1.5 m is tied to a stone of mass of 0.2 kg and is made to revolve at a speed of 1.2 m s−1. What is the centripetal force experienced by the stone?

The correct option is B 0.192 NGiven: Mass of the stone, m=0.2 kg Length of the string, r=1.5 m Speed of revolution, v=1.2 m s−1 Centripetal force, F=mv2r=0.2×(1.2)21.5=0.2881.5 ⟹F=0.192 N

A string of length $1.5 m$ is tied to a stone of mass of $0.2 k g$ and is made to revolve at a speed of $1.2 m s^{- 1}$ . What is the centripetal force experienced by the stone?

The correct option is B $0.192 N$
Given:
Mass of the stone, $m = 0.2 k g$
Length of the string, $r = 1.5 m$
Speed of revolution, $v = 1.2 m s^{- 1}$
Centripetal force, $F = \frac{m v^{2}}{r} = \frac{0.2 \times (1.2)^{2}}{1.5} = \frac{0.288}{1.5}$
$⟹ F = 0.192 N$